mirror of
https://github.com/priyanshujain/messageboardbench.git
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Checkpoint experiments through SWE pilot v2
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pj committed
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"answer": "def count_beautiful_integers(low: int, high: int, k: int) -> int:\n \"\"\" Count the number of beautiful integers in the range [low, high].\n \n A number is beautiful if it meets both conditions:\n 1. The count of even digits equals the count of odd digits\n 2. The number is divisible by k\n \n Args:\n low: Lower bound of the range (inclusive), 0 < low <= high <= 10^9\n high: Upper bound of the range (inclusive)\n k: Divisor to check, 0 < k <= 20\n \n Returns:\n The count of beautiful integers in the given range\n \n >>> count_beautiful_integers(10, 20, 3)\n 2\n >>> count_beautiful_integers(1, 10, 1)\n 1\n >>> count_beautiful_integers(5, 5, 2)\n 0\n \"\"\"\n\n def count_upto(n: int) -> int:\n if n <= 0:\n return 0\n digits = list(map(int, str(n)))\n L = len(digits)\n from functools import lru_cache\n\n @lru_cache(maxsize=None)\n def dp(pos, balance, mod, started, tight):\n if pos == L:\n if not started:\n # the number 0 itself (not a positive integer)\n return 0\n return 1 if (balance == 0 and mod == 0) else 0\n limit = digits[pos] if tight else 9\n total = 0\n for d in range(limit + 1):\n ntight = tight and (d == limit)\n if not started and d == 0:\n total += dp(pos + 1, balance, mod, False, ntight)\n else:\n if d % 2 == 0:\n nb = balance + 1\n else:\n nb = balance - 1\n nmod = (mod * 10 + d) % k\n total += dp(pos + 1, nb, nmod, True, ntight)\n return total\n\n return dp(0, 0, 0, False, True)\n\n return count_upto(high) - count_upto(low - 1)\n",
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"func.py": "def count_beautiful_integers(low: int, high: int, k: int) -> int:\n \"\"\" Count the number of beautiful integers in the range [low, high].\n \n A number is beautiful if it meets both conditions:\n 1. The count of even digits equals the count of odd digits\n 2. The number is divisible by k\n \n Args:\n low: Lower bound of the range (inclusive), 0 < low <= high <= 10^9\n high: Upper bound of the range (inclusive)\n k: Divisor to check, 0 < k <= 20\n \n Returns:\n The count of beautiful integers in the given range\n \n >>> count_beautiful_integers(10, 20, 3)\n 2\n >>> count_beautiful_integers(1, 10, 1)\n 1\n >>> count_beautiful_integers(5, 5, 2)\n 0\n \"\"\"\n\n def count_upto(n: int) -> int:\n if n <= 0:\n return 0\n digits = list(map(int, str(n)))\n L = len(digits)\n from functools import lru_cache\n\n @lru_cache(maxsize=None)\n def dp(pos, balance, mod, started, tight):\n if pos == L:\n if not started:\n # the number 0 itself (not a positive integer)\n return 0\n return 1 if (balance == 0 and mod == 0) else 0\n limit = digits[pos] if tight else 9\n total = 0\n for d in range(limit + 1):\n ntight = tight and (d == limit)\n if not started and d == 0:\n total += dp(pos + 1, balance, mod, False, ntight)\n else:\n if d % 2 == 0:\n nb = balance + 1\n else:\n nb = balance - 1\n nmod = (mod * 10 + d) % k\n total += dp(pos + 1, nb, nmod, True, ntight)\n return total\n\n return dp(0, 0, 0, False, True)\n\n return count_upto(high) - count_upto(low - 1)\n",
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"answer": "def count_beautiful_integers(low: int, high: int, k: int) -> int:\n \"\"\" Count the number of beautiful integers in the range [low, high].\n \n A number is beautiful if it meets both conditions:\n 1. The count of even digits equals the count of odd digits\n 2. The number is divisible by k\n \n Args:\n low: Lower bound of the range (inclusive), 0 < low <= high <= 10^9\n high: Upper bound of the range (inclusive)\n k: Divisor to check, 0 < k <= 20\n \n Returns:\n The count of beautiful integers in the given range\n \n >>> count_beautiful_integers(10, 20, 3)\n 2\n >>> count_beautiful_integers(1, 10, 1)\n 1\n >>> count_beautiful_integers(5, 5, 2)\n 0\n \"\"\"\n\n def count_upto(n: int) -> int:\n if n <= 0:\n return 0\n digits = list(map(int, str(n)))\n L = len(digits)\n from functools import lru_cache\n\n @lru_cache(maxsize=None)\n def dp(pos, balance, mod, started, tight):\n if pos == L:\n if not started:\n # the number 0 itself (not a positive integer)\n return 0\n return 1 if (balance == 0 and mod == 0) else 0\n limit = digits[pos] if tight else 9\n total = 0\n for d in range(limit + 1):\n ntight = tight and (d == limit)\n if not started and d == 0:\n total += dp(pos + 1, balance, mod, False, ntight)\n else:\n if d % 2 == 0:\n nb = balance + 1\n else:\n nb = balance - 1\n nmod = (mod * 10 + d) % k\n total += dp(pos + 1, nb, nmod, True, ntight)\n return total\n\n return dp(0, 0, 0, False, True)\n\n return count_upto(high) - count_upto(low - 1)\n",
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"func.py": "def count_beautiful_integers(low: int, high: int, k: int) -> int:\n \"\"\" Count the number of beautiful integers in the range [low, high].\n \n A number is beautiful if it meets both conditions:\n 1. The count of even digits equals the count of odd digits\n 2. The number is divisible by k\n \n Args:\n low: Lower bound of the range (inclusive), 0 < low <= high <= 10^9\n high: Upper bound of the range (inclusive)\n k: Divisor to check, 0 < k <= 20\n \n Returns:\n The count of beautiful integers in the given range\n \n >>> count_beautiful_integers(10, 20, 3)\n 2\n >>> count_beautiful_integers(1, 10, 1)\n 1\n >>> count_beautiful_integers(5, 5, 2)\n 0\n \"\"\"\n\n def count_upto(n: int) -> int:\n if n <= 0:\n return 0\n digits = list(map(int, str(n)))\n L = len(digits)\n from functools import lru_cache\n\n @lru_cache(maxsize=None)\n def dp(pos, balance, mod, started, tight):\n if pos == L:\n if not started:\n # the number 0 itself (not a positive integer)\n return 0\n return 1 if (balance == 0 and mod == 0) else 0\n limit = digits[pos] if tight else 9\n total = 0\n for d in range(limit + 1):\n ntight = tight and (d == limit)\n if not started and d == 0:\n total += dp(pos + 1, balance, mod, False, ntight)\n else:\n if d % 2 == 0:\n nb = balance + 1\n else:\n nb = balance - 1\n nmod = (mod * 10 + d) % k\n total += dp(pos + 1, nb, nmod, True, ntight)\n return total\n\n return dp(0, 0, 0, False, True)\n\n return count_upto(high) - count_upto(low - 1)\n",
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"test.py": "from func import count_beautiful_integers\n\ndef test_func(candidate):\n # Example test cases\n assert candidate(10, 20, 3) == 2\n assert candidate(1, 10, 1) == 1\n assert candidate(5, 5, 2) == 0\n \n # Additional test cases\n assert candidate(1, 1, 1) == 0\n assert candidate(19, 50, 2) == 6\n assert candidate(94, 94, 9) == 0\n assert candidate(94, 100, 1) == 3\n assert candidate(52, 396, 9) == 5\n assert candidate(47, 735, 2) == 15\n assert candidate(90, 110, 16) == 1\n assert candidate(934, 991, 1) == 0\n assert candidate(1, 1000000000, 1) == 24894045\n assert candidate(33340762, 612987024, 1) == 18196584\n assert candidate(36954768, 642296821, 14) == 1240042\n assert candidate(17946863, 807558969, 17) == 1319380\n\nif __name__ == \"__main__\":\n test_func(count_beautiful_integers)\n print(\"All tests passed!\")\n"
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"answer": "def count_beautiful_integers(low: int, high: int, k: int) -> int:\n \"\"\" Count the number of beautiful integers in the range [low, high].\n \n A number is beautiful if it meets both conditions:\n 1. The count of even digits equals the count of odd digits\n 2. The number is divisible by k\n \n Args:\n low: Lower bound of the range (inclusive), 0 < low <= high <= 10^9\n high: Upper bound of the range (inclusive)\n k: Divisor to check, 0 < k <= 20\n \n Returns:\n The count of beautiful integers in the given range\n \n >>> count_beautiful_integers(10, 20, 3)\n 2\n >>> count_beautiful_integers(1, 10, 1)\n 1\n >>> count_beautiful_integers(5, 5, 2)\n 0\n \"\"\"\n\n def count_upto(n: int) -> int:\n if n <= 0:\n return 0\n digits = list(map(int, str(n)))\n L = len(digits)\n from functools import lru_cache\n\n @lru_cache(maxsize=None)\n def dp(pos, balance, mod, started, tight):\n if pos == L:\n if not started:\n # the number 0 itself (not a positive integer)\n return 0\n return 1 if (balance == 0 and mod == 0) else 0\n limit = digits[pos] if tight else 9\n total = 0\n for d in range(limit + 1):\n ntight = tight and (d == limit)\n if not started and d == 0:\n total += dp(pos + 1, balance, mod, False, ntight)\n else:\n if d % 2 == 0:\n nb = balance + 1\n else:\n nb = balance - 1\n nmod = (mod * 10 + d) % k\n total += dp(pos + 1, nb, nmod, True, ntight)\n return total\n\n return dp(0, 0, 0, False, True)\n\n return count_upto(high) - count_upto(low - 1)\n",
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"func.py": "def count_beautiful_integers(low: int, high: int, k: int) -> int:\n \"\"\" Count the number of beautiful integers in the range [low, high].\n \n A number is beautiful if it meets both conditions:\n 1. The count of even digits equals the count of odd digits\n 2. The number is divisible by k\n \n Args:\n low: Lower bound of the range (inclusive), 0 < low <= high <= 10^9\n high: Upper bound of the range (inclusive)\n k: Divisor to check, 0 < k <= 20\n \n Returns:\n The count of beautiful integers in the given range\n \n >>> count_beautiful_integers(10, 20, 3)\n 2\n >>> count_beautiful_integers(1, 10, 1)\n 1\n >>> count_beautiful_integers(5, 5, 2)\n 0\n \"\"\"\n\n def count_upto(n: int) -> int:\n if n <= 0:\n return 0\n digits = list(map(int, str(n)))\n L = len(digits)\n from functools import lru_cache\n\n @lru_cache(maxsize=None)\n def dp(pos, balance, mod, started, tight):\n if pos == L:\n if not started:\n # the number 0 itself (not a positive integer)\n return 0\n return 1 if (balance == 0 and mod == 0) else 0\n limit = digits[pos] if tight else 9\n total = 0\n for d in range(limit + 1):\n ntight = tight and (d == limit)\n if not started and d == 0:\n total += dp(pos + 1, balance, mod, False, ntight)\n else:\n if d % 2 == 0:\n nb = balance + 1\n else:\n nb = balance - 1\n nmod = (mod * 10 + d) % k\n total += dp(pos + 1, nb, nmod, True, ntight)\n return total\n\n return dp(0, 0, 0, False, True)\n\n return count_upto(high) - count_upto(low - 1)\n",
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"test.py": "from func import count_beautiful_integers\n\ndef test_func(candidate):\n # Example test cases\n assert candidate(10, 20, 3) == 2\n assert candidate(1, 10, 1) == 1\n assert candidate(5, 5, 2) == 0\n \n # Additional test cases\n assert candidate(1, 1, 1) == 0\n assert candidate(19, 50, 2) == 6\n assert candidate(94, 94, 9) == 0\n assert candidate(94, 100, 1) == 3\n assert candidate(52, 396, 9) == 5\n assert candidate(47, 735, 2) == 15\n assert candidate(90, 110, 16) == 1\n assert candidate(934, 991, 1) == 0\n assert candidate(1, 1000000000, 1) == 24894045\n assert candidate(33340762, 612987024, 1) == 18196584\n assert candidate(36954768, 642296821, 14) == 1240042\n assert candidate(17946863, 807558969, 17) == 1319380\n\nif __name__ == \"__main__\":\n test_func(count_beautiful_integers)\n print(\"All tests passed!\")\n"
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Reference in new issue
Block a user